Layosa136449130034idn
Answered

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B. Determine the empirical formula of a compound
with the following percent composition by mass: K
24.75%, Mn 34.77%, O 40.51%.
​

Sagot :

Poisonedrenidn

SOLUTION

To determine the empirical formula of a compound with the given percent composition by mass, we need to convert the percent composition to grams and then divide each mass by the smallest mass to get the simplest whole number ratio.

First, convert the percent composition to grams:

  • K: 24.75% of 100g = 24.75g
  • Mn: 34.77% of 100g = 34.77g
  • O: 40.51% of 100g = 40.51g

Next, divide each mass by the smallest mass to get the simplest whole number ratio:

  • K: 24.75g / 34.77g = 0.714
  • Mn: 34.77g / 34.77g = 1
  • O: 40.51g / 34.77g = 1.16

The smallest whole number ratio is 1:1:1.16, which simplifies to K:Mn:O = 1:1:1.16. However, the empirical formula should be expressed as a whole number ratio, so we need to multiply each ratio by 10 to get the whole number ratio 10:10:11.6.

Finally, we need to simplify this ratio to the lowest whole number ratio. The ratio 10:10:11.6 can be simplified by dividing each number by their greatest common divisor, which is 2. This gives us the simplified ratio 5:5:5.8.

Therefore, the empirical formula of the compound is KMnO5.

Barbiegrace069idn

Answer:

the empirical formula of the compound is K_{0.63}Mn_{0.63}O_{2.53}.

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