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(2x-1) (2x+1) = (x-2)²

Sagot :

Answer:

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To solve the equation (2x-1)(2x+1) = (x-2)², we can follow these steps:

  • Expand the left side of the equation:
  • (2x-1)(2x+1) = 2x * 2x + 2x * 1 - 1 * 2x - 1 * 1
  • (2x-1)(2x+1) = 4x² + 2x - 2x - 1
  • (2x-1)(2x+1) = 4x² - 1

Expand the right side of the equation:

  • (x-2)² = (x-2)(x-2) = x * x - 2 * x - 2 * x + 2 * 2
  • (x-2)² = x² - 4x + 4

Now, we can set the left and right sides of the equation equal to each other:

  • 4x² - 1 = x² - 4x + 4

Simplify the equation by moving all terms to one side:

  • 4x² - 1 - x² + 4x - 4 = 0
  • 3x² + 4x - 5 = 0

Now, we have a quadratic equation that can be solved using the quadratic formula:

  • x = (-b ± √(b² - 4ac)) / 2a

In this case, a = 3, b = 4, and c = -5. Plugging these values into the formula will give us the solutions for x.

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Step-by-step explanation:

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