Sumali sa IDNStudy.com at makuha ang mga sagot ng eksperto. Makakuha ng impormasyon mula sa aming mga eksperto, na nagbibigay ng maaasahang sagot sa lahat ng iyong mga tanong.

Completing the square (Quadratic Formula) T__T
1. 3x^2 - 9x + 27 = 0
2. 2x^2 + 10x - 4 = 0
3. 4x^2 - 8x + 3 = 0

Pahelp :) Thanksss.


Sagot :

[tex]ax^2+bx+c=0[/tex]

Quadratic Formula:   [tex]x = \frac{-b\pm \sqrt{b^2-4ac} }{2a} [/tex]

1) a = 3   ;   b = -9   ;   c = 27
   [tex]x = \frac{9\pm \sqrt{81-4(3)(27)} }{2(3)}[/tex]
  
   [tex]x = \frac{9\pm \sqrt{-243} }{6}[/tex]
  
   [tex]x = \frac{9\pm 9\sqrt{-3} }{6}= \frac{3\pm 3\sqrt{-3} }{2}[/tex]

   [tex]\boxed{x_1= \frac{3+ 3\sqrt{-3} }{2}= \frac{3+ 3i\sqrt{3} }{2}}[/tex]

   [tex]\boxed{x_2= \frac{3- 3\sqrt{-3} }{2}= \frac{3-3i\sqrt{3} }{2}}[/tex]


2) a = 2   ;   b = 10   ;   c = -4
   [tex]x = \frac{-10\pm \sqrt{100-4(2)(-4)} }{2(2)}[/tex]

   [tex]x = \frac{-10\pm \sqrt{132} }{4}[/tex]

   [tex]x = \frac{-10\pm 2\sqrt{33} }{4}=\frac{-5\pm\sqrt{33} }{2}[/tex]

   [tex]\boxed{x_1= \frac{-5+\sqrt{33} }{2}}[/tex]

   [tex]\boxed{x_2= \frac{-5-\sqrt{33} }{2}}[/tex]

3) a = 4   ; b = -8   ;   c = 3
   [tex]x = \frac{8\pm \sqrt{64-4(4)(3)} }{2(4)}[/tex]

   [tex]x = \frac{8\pm \sqrt{16} }{8}[/tex]

   [tex]x = \frac{8\pm4 }{8}=\frac{2\pm1 }{2}[/tex]

   [tex]x_1 =\frac{2+1 }{2}=\boxed{\frac{3}{2}}[/tex]

   [tex]x_2 =\frac{2-1 }{2}=\boxed{\frac{1}{2}}[/tex]