Anglojenineidn
Answered

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what is the equation of the line passing through (4,-7) and perpendicular to the line through (0,1) and (3,-3).

Sagot :

AnneCidn
m of perpendicular line = [tex] \frac{1-(-3)}{0-3}= \frac{4}{-3} = \frac{-4}{3} [/tex]

m of line = [tex] \frac{3}{4} [/tex]

equation of line:  [tex]y-y_1=m(x-x_1)[/tex]

 [tex]y-(-7)=\frac{3}{4}(x-4)[/tex]

 [tex]y+7=\frac{3}{4}x-3[/tex]

 [tex]y=\frac{3}{4}x-3-7[/tex]

 [tex]\boxed{y=\frac{3}{4}x-10}[/tex]