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find the missing terms in each arithmetic sequence _,_,_,8,12,16​

Sagot :

Answer:

-4, 0, 4, 8, 12, 16

Step-by-step explanation:

  • Simple way:

From the number of the first show (4) to the end (16)

check the interval first

 16 - 12 = 4

 12 - 8  = 4

we found the interval is 4

so, to find 3 others is by substracted with 4

  8 - 4   = 4

  4 - 4   = 0

  0 - 4   = -4

then we already get the answer:

-4, 0, 4

  • Hard way:

find a, a is the arithmetic

find n, n is the sequence

find d, d is the number that first shows up

used this formula:

a n = a 1 + (n - 1) d

d = 4

n = 6 (sequence 6)

a n = a 6

  • find a 1 (sequence 1)

  a n = a 1 + (6 - 1) 4

  a 6 = a 1 + 20

   a 6 - a 1 = 20

a 5 = 20

(a).(5) = 20

a  = 20/ -5

    a  =  - 4

a could be announced as a 1

we add -4 for sequence 1 =

       -4, _, _, 8, 12, 16

  • find a 2 (sequence 2)

  a n = a 1 + (n - 1) d

     d = 4

    a1 = -4

      n = 2

   a 2 = -4 +(2-1)4

   a 2 = −4 + (1)(4)

   a 2 = −4 + 4

   a 2 = 0

add 0 for sequence 2 =

-4, 0, _, 8, 12, 16

  • Find a 3 (sequence 3)

    d = 4

    a 1 = -4

     n = 3

   a 3 = (-4) + (3 - 1) 4

   a 3 = −4 + (2)(4)

   a 3 = −4 + 8

   a 3 = 4

add 4 for sequence 3 =

-4, 0, 4, 8, 12, 16

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