Cessvaldoriaidn
Answered

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1. The area of a rectangular pool is x² + x-12 cm². The width of the garden is x + 4 cm. Find the length of the rectangular garden. a. State what is asked to find. b. State the given facts. c. Write a working equation. d. Solve the equation. e. State your answer.​

1 The Area Of A Rectangular Pool Is X X12 Cm The Width Of The Garden Is X 4 Cm Find The Length Of The Rectangular Garden A State What Is Asked To Find B State T class=

Sagot :

Smokerzidn

Answer:

[tex] \large \boxed{x - 3}[/tex]

Step-by-step explanation:

a) State what's asked to find [tex] \downarrow[/tex]

  • The length of the rectangular garden.

b) State the given facts [tex] \downarrow[/tex]

  • Area of a rectangular pool (garden) = x² + x - 12 cm²
  • Width of the garden = x + 4 cm

c) Write a working equation [tex] \downarrow[/tex]

Area of the garden = length of the garden × width of the garden. Let's take the length as 'l'. So the equation is...

  • x² + x - 12 = l × (x + 4)

d) Solve the equation [tex] \downarrow[/tex]

[tex]\tt {x}^{2} + x - 12 = l \times (x + 4) \\ \\ \sf \: Bring \: (x + 4) \: towards \: the \: left \: side \\ \sf\: of \: the \: equation. \\ \\ \tt \frac{ {x}^{2} + x - 12 }{x + 4} = l \\ \\ \sf \: Factor \: the \: expressions \: that \: are \\ \sf \: not \: already \: factored. \\ \\ \tt \frac{\left(x-3\right)\left(x+4\right)}{(x+4)} = l\\ \\ \sf Cancel \: out \: (x + 4) \: in \: both \: the \\ \sf \: numerator \: and \: denominator. \\ \\ \large \boxed{\boxed{ \bold{\: (x-3 )= l}}}[/tex]

e) State your answer [tex] \downarrow[/tex]

The length of the rectangular garden is x - 3 cm.

Note :-

I think there's a mistake in the question. It should be the area of the rectangular garden & not area of the rectangular pool because here we are asked to measure the length of the garden.

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