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what is the answer of 4x³ - 3 = 9​

Sagot :

Answer/Explanation:

Evaluate

  • [tex]4x³ \: − \: 3=9[/tex]

Move the constant to the right side

  • [tex]4x³=9+3[/tex]

Add the terms

  • [tex]4x³=12[/tex]

Divide both sides

  • [tex]\frac{4x³}{4} = \frac{12}{4}[/tex]

Simplify

  • [tex]\frac{4x³}{4} = 3[/tex]

Simplify

  • [tex]x³=3[/tex]

Raise both sides of the equation to the [tex]\frac{1}{3}[/tex]-th power to eliminate the isolated [tex]\frac{1}{3}[/tex]-th root

  • [tex]({x}^{3}) {}^{ \frac{1}{3}} = 3 {}^{ \frac{1}{3} } [/tex]

Solution

  • [tex]x = \sqrt[3]{3} [/tex]

[tex]\large\bold\green{{Answer/Explanation:}}[/tex]

Evaluate

  • [tex]4x³ \: − \: 3=9[/tex]

Move the constant to the right side

  • [tex]4x³=9+3[/tex]

Add the terms

  • [tex]4x³=12[/tex]

Divide both sides

  • [tex]\frac{4x³}{4} = \frac{12}{4}[/tex]

Simplify

  • [tex]\frac{4x³}{4} = 3[/tex]

Simplify

  • [tex]x³=3[/tex]

Raise both sides of the equation to the [tex]\frac{1}{3}[/tex]-th power to eliminate the isolated [tex]\frac{1}{3}[/tex]-th root

  • [tex]({x}^{3}) {}^{ \frac{1}{3}} = 3 {}^{ \frac{1}{3} } [/tex]

Solution

  • [tex]x = \sqrt[3]{3} [/tex]