[tex] \huge \mathtt \gray {SOLUTION : }[/tex]
Dahil ang kabuuang distansya ng dalawa ang hinahanap, kailangan lang natin i-add ang [tex] \: \tt \gray{1 \frac{3}{8} } \: [/tex] at [tex] \: \tt \gray{\frac{1}{4} } [/tex].
[tex]\tt \gray{1 \frac{3}{8} + \frac{1}{4} }[/tex]
Convert the mixed number into improper fractions. Then the equation becomes:
[tex]\tt \gray{ \frac{11}{8} + \frac{1}{4} }[/tex]
Let's now solve it
[tex]\tt \gray{ = \frac{(11 \times 4) + (1 \times 8)}{8 \times 4} }[/tex]
[tex]\tt \gray{ = \frac{44 + 8}{32} }[/tex]
[tex]\tt \gray{ = \frac{52}{32} }[/tex]
Simplify [tex] \tt \gray{ \: \frac{52}{32} } [/tex], the final answer is:
[tex]{ \boxed{ \underline{\tt \gray{ 1\frac{5}{8} \: km }}}}[/tex]
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