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Modify the function ispalindrome of example 6-6 so that when determining whether a string is a palindrome, cases are ignored, that is, uppercase and lowercase letters are considered the same. the ispalindrome function from example 6-6 has been included below for your convenience.

Sagot :

Answer:

#include<iostream>

#include <string>

using namespace std;

bool isPalindrome(string str)

{

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

if (tolower(str[i]) != tolower(str[length - 1 - i]))

{

return false;

}

}

return true;

}

int main()

{

 if (isPalindrome("Madam"))

   cout << "madam" << " is a palindrome." << endl;

 if (isPalindrome("abBa"))

   cout << "abBa" << " is a palindrome." << endl;

 if (isPalindrome("22"))

   cout << "22" << " is a palindrome." << endl;

 if (isPalindrome("67876"))

   cout << "67876" << " is a palindrome." << endl;

 if (isPalindrome("444244"))

   cout << "444244" << " is not a palindrome." << endl;

   else

   cout << "444244" << " is not a palindrome." << endl;

 

 if (isPalindrome("trYmeuemyRT"))

   cout << "trYmeuemyRT" << " is a palindrome." << endl;

 return 0;

}

Explanation: