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how are you going to use quadratic formula in determining whether a quadratic equation has no real solutions? give 2 examples if quadratic equations of no real solutions



Sagot :

The discriminant of the quadratic formula determines the nature of the roots of a quadratic equation. It is the expression inside that radical sign.

[tex]discriminant = b^{2} -4ac[/tex]

A quadratic equation has no real solutions if the discriminat is negative.

Examples of equations are

[tex] x^{2} -x +2[/tex]
(discriminant = -7)

[tex] x^{2} +2x+2[/tex]
(discriminant = -4)
if k<0, then x²=k has no real solution

for example:

s²+9=0
write the equation in the form x²=k

s²+9=0⇒ s²+9-9=0-9
               s= -9

since -9 is less than 0 then the equation s²²=-9 has no real solution or roots
there is no real number when squared gives 9