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Lines p and q are cut by a transversal, find the value of x that makes p || q.

1. angle 4 and angle 5 are alternative interior angles, m angle 4 =5x - 11 and m angle 5 = 3x + 7

2. angle 4 and angle 6 are same side interior angles, m angle 4 = 6x + 3 and m angle 6 = 4x + 7

3. angle 2 and angle 6 are corresponding angles, m angle 2 = 3x - 15 and m angle 6 = x + 55​

Sagot :

Answer:

Step-by-step explanation:

View image Asheng020
View image Asheng020

Answer:

Direction: 1. Lines p and q are cut by transversal r. Find the value of x that makes p ll q

Answer:

a.<2 and <7 are alternate interior angles,  m<2 = 5x – 11 and m<7 = 3x + 7.

x=9

b.<1 and <4 are some-side exterior angles,  m<1 = 6x + 3 and m<4 = 4x + 7.

x=2

Solution:

#TO FIND THE VALUE OF "X"

a. Given: (m<2 = 5x – 11 and m<7 = 3x + 7)

m<2=m<7

5x-11=3x+7

5x-3x=7+11

2x=18

2x/2=18/2 (Divide both sides by 2)

x=9

#Check first

#Substitute x by 9

#If x=9

m<2=m<7

5x-11=3x+7

5(9)-11=3(9)+7

(45)-11=(27)+7

34=34

b. Given: (m<1 = 6x + 3 and m<4 = 4x + 7)

m<1=m<4

6x+3=4x+7

6x-4x=7-3

2x=4

2x/2=4/2 (Divide both sides by 2)

x=2

#Check first,

#Substitute x by 2

#If x=2

m<1=m<4

6x+3=4x+7

6(2)+3=4(2)+7

(12)+3=(8)+7

15=15

Step-by-step explanation:

They are both equal and correct to each other when you finding the value of x then replaced x by any number that it depends on the given equation.

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