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A solution is prepared by mixing 0.2 moles of hcl into water until the final volume of the solution is 5 l. what is the poh of the solution?

Sagot :

SOLUTION:

Step 1: Calculate the concentration of HCl solution.

[tex]\begin{aligned} [\text{HCl}]_{\text{initial}} & = \frac{n_{\text{HCl}}}{V_{\text{solution}}} \\ & = \frac{\text{0.2 mol}}{\text{5 L}} \\ & = \text{0.04 mol/L} \\ & = 0.04 \: M \end{aligned}[/tex]

Step 2: Determine the hydrogen ion concentration at equilibrium.

[tex]\begin{aligned} [\text{H}^+] & = [\text{HCl}]_{\text{initial}} \\ & = 0.04 \: M \end{aligned}[/tex]

Step 3: Calculate the pH of solution.

[tex]\begin{aligned} \text{pH} & = -\text{log} \: [\text{H}^+] \\ & = -\text{log} \: (0.04) \\ & = 1.4 \end{aligned}[/tex]

Step 4: Calculate the pOH of solution.

[tex]\begin{aligned} \text{pOH} & = 14 - \text{pH} \\ & = 14 - 1.4 \\ & = \boxed{12.6} \end{aligned}[/tex]

Hence, the pOH of the solution is 12.6

[tex]\\[/tex]

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