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calculate the decrease in temperature when 4.00L at 22.0 °C gas sample is compressed to 2.00 L. suppose pressure is constant​

Sagot :

Answer:

CHARLE'S LAW

T₂ = TiV₂ ÷ Vi

    = (295.15 k)(2.00 L) ÷ 4.00 L

    = 147.575 k

    = -125.575 °C or -125.58 °C

Explanation:

Δ change the celsius to kelvin by adding 273.15

Δ by changing the kelvin to celsius, you just have to subtract 273.15