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A 7.25 L sample of nitrogen gas is determined to contain 0.75 mole of nitrogen. how many moles of nitrogen gas would there be in a 20L sample provided the temperature and pressure remains the same ​

Sagot :

I really don't know just needed scores

Answer:

2.07 mol

Explanation:

Sample 1: n₁ = 0.75 mol, V₁ = 7.25 L

Sample 2: n₂ = ? mol, V₂ = 20 L

For gases at constant pressure and temperature (Avogadro's law): n₁/n₂ = V₁/V₂

Then, n₂ = n₁ × (V₂/V₁)

No. of moles in the 20 L sample, n₂ = (0.75 mol) × (20/7.25) = 2.07 mol