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Three consecutive integers wherein the first integer less than the 3rd integer is the same as the difference of the 2nd integer and twelve.

Sagot :

What are the 3 odd integers in which thrice the product of the last two is six less than the product of the first two integers?✍

  • The three odd integers are 15, 17, 19.

Let
n=first integer
n+1 second integer
n+2 third integer

(Third-First)=Second-12
(n+2-n)=n+1-12
2=n-11
13=n

13 is the first integer
13+1=14 is the second
13+2=15 is the third

Check

15-13=14-12
2=2