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Answer:
The volume of the balloon at 50 degree will be larger than the original volume (200 mL).
Explanation:
This problem is an application of Charles' Law. Charles' law is a gas law that describes the relationship of the volume and the temperature of a gas at constant pressure. The temperature used for this law should be absolute or in the unit Kelvin.
The mathematical equation of Charles' Law is:
\frac{V1}{T1}
T1
V1
= \frac{V2}{T2}
T2
V2
Let us solve for the final volume of the balloon.
V2 = \frac{V1 T2}{T1}
T1
V1T2
V2 = \frac{(200 mL) (30 +273.15)}{50+273.15}
50+273.15
(200mL)(30+273.15)
V2 = 213.195 mL
Note that we added 273.15 to the temperatures to make it Kelvin.
Now that we know the value of the final volume, we can now compare the final volume to the initial volume. 213.195 mL is obviously lager than 200 mL, hence, the volume of the balloon increased as the temperature also increased.
Finally we can conclude that at 50 degrees, the volume of the balloon became larger than the original volume