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Sagot :
Answer:
Solution
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We have two graphs actual and forecast, In the graph x−axis represents days and y−axis represents the temperature
Scale :
On x−axis 4 cm =1 day
On y−axis 2 cm =5
0
C
To find the temperature at particular day:
Trace the vertical line parallel to y−axis passing from the point on x−axis, find the point where this vertical line intersects the graph.
Now from that point trace a horizontal line parallel to x−axis, this line intersects the y−axis at required point.
To find the day at particular temperature:
Trace the horizontal line parallel to x−axis passing from the temperature point on y−axis, find the point where this horizontal line intersects the graph.
Now from that point trace a vertical line parallel to y−axis, this line intersects the x−axis at required point.
Now,
a) Forecast temperature and actual temperature are same where the graphs of both intersects which is Tuesday, Friday and Sunday
b) Follow step 1 to find temperature for graph forecast on days of week,
Mon −15
0
C
Tue −20
0
C
Wed −25
0
C
Thu −22.5
0
C
Fri −15
0
C
Sat −30
0
C
Sun −35
0
C
So, maximum forecast temperature during the week is 35
0
C
c) Follow step 1 to find temperature for actual graph on days of week
Mon−17.5
0
C
Tue −20
0
C
Wed−30
0
C
Thu −15
0
C
Fri −15
0
C
Sat −25
0
C
Sun −35
0
C
So, minimum actual temperature during the week is 15
0
C
d) Difference between actual and forecast temperatures during the week
Mon, 17.5−15=2.5
0
C
Tue, 20−20=0
0
C
Wed, 30−25=5
0
C
Thu, 15−22.5=−7.5
0
C
Fri, 15−15=0
0
C
Sat, 25−30=−5
0
C
Sun, 35−35=0
0
C
So, actual temperature differ most from forecast temperature is 7.5
0
C which is on Thursday.
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