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Based on the balanced equation, 1 mole of Fe₂O₃ is stoichiometrically equivalent to 3 moles of CO₂.
The volume of 1 mole of any gas at STP is 22.4 L.
The molar mass of Fe₂O₃ is 160 g/mol.
[tex]\begin{aligned} \text{volume of} \: \text{CO}_2 & = \text{3.46 g} \: \text{Fe}_2\text{O}_3 \times \frac{\text{1 mol} \: \text{Fe}_2\text{O}_3}{\text{160 g} \: \text{Fe}_2\text{O}_3} \times \frac{\text{3 mol} \: \text{CO}_2}{\text{1 mol} \: \text{Fe}_2\text{O}_3} \times \frac{\text{22.4 L}}{\text{1 mol} \: \text{CO}_2} \\ & = \boxed{\text{1.45 L}} \end{aligned}[/tex]
Hence, the answer is b. 1.45 L.
[tex]\\[/tex]
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