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Sagot :
Answer:
The side of the reaction with fewer moles of gas
Explanation:
When there is an increase in pressure, the equilibrium will shift towards the side of the reaction with fewer moles of gas. When there is a decrease in pressure, the equilibrium will shift towards the side of the reaction with more moles of gas.
According to Lé Chàtelier's principle, if pressure is increased, then the equilibrium shifts to the side with the fewer number of moles of gas.
This means if we add reactant, equilibrium goes right, away from the reactant. If we add product, equilibrium goes left, away from the product. If we remove product, equilibrium goes right, making product. If we remove reactant, equilibrium goes left, making reactant.
According to the Lé Chàtelier's principle, the net reaction will move in the direction that decreases the stress placed on the system. So if the stress is increased amount of one of the reactants, the equilibrium will shift to the right to get rid of some of that reactant.
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