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five consecutive odd integers whose sum is 55

Sagot :

let x = first odd integer among the five
x + 2 = second odd integer
x + 4 = third odd integer
x + 6 = fourth odd integer
x + 8 = fifth odd integer

x + x + 2 + x + 4 + x + 6 + x + 8 = 55
5x + 20 = 55
5x = 55 - 20
[tex] \frac{5x}{5} = \frac{35}{5} [/tex]
x = 7 - first
x + 2 = 9 - second
x + 4 = 11 - third
x + 6 = 13 - fourth
x + 8 = 15 - fifth

7 + 9 + 11 + 13 + 15 = 55
55 = 55

Therefore, the answer to your question are 7, 9, 11, 13, 15.