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one liter of 10% alcohol is mixed with 3 liters of 30% alcohol.What is the percentage of alcohol in the resulting mixture?

Sagot :

Since you've added the two mixture then,
Let 'x' be the percentage of alcohol of the mixture
1li (0.10) + 3li (0.30) = 4li (x)
0.10 + 0.90 = 4x
1 = 4x 
1/4 = x
0.25 = x 
or in percentage, x=25%
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Therefore the resulting mixture is of 25% alcohol.