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y varies inversely as x and the following conditions exist. Find the equation of variation of y = 6 when x = 15

Sagot :

y = k/x     where k is the constant of variation

y = 6;      x = 15

To find the constant of variation:

y = kx           

k = y/x
 
k = 6/15

k = 2/5
y = kx
Based on the problem, y = 6; x = 15. To find the constant of variation...

y = kx           

k = y/x
k = 6/15
k = 2/5