Answered

IDNStudy.com, ang iyong gabay para sa malinaw at eksaktong mga sagot. Magtanong at makatanggap ng eksaktong sagot mula sa aming mga bihasang miyembro ng komunidad.

There were 8000 tickets sold for the Uaap championship. The tickets were 150 for the bleachers, 300 for the upper box and 500 for the lower box. The number of bleacher tickets sold was three times the number of th lower box tickets sold. If the total amount collected was 2150000, how many of each type of ticket were sold?

Sagot :

ANSWER:

The number of tickets sold per seat type:
Lower box = 1,000 tickets
Bleacher = 3,000 tickets
Upper box = 4,000 tickets

------------------------------- 
SOLUTION:
Total: 8,000 tickets.
Number of tickets per seat type:
Lower box = x
Bleacher = 3x
Upper Box = y  or 8,000 - 4x

               x + 3x + y = 8,000
               4x + y = 8,000
               y = 8,000 - 4x

Ticket prices:
Lower box: 500 (x)  or 500x
Bleacher: 150 (3x) or 450x
Upper: 300 (8,000 - 4x) or 2,400,000-1,200x

Equation:

500x + 450x + 2,400,000 - 1200x = 2,150,00
950x - 1,200x = 2,150.000
- 250x = -250,000
-250x/-250 = -250,000/-250
x = 1,000

Substitute 1,000 to x in:
y = 8,000 - 4 (1,000)
y = 8,000 - 4,000
y = 4,000
 
Substitute values of x and y to number of tickets:
Lower box: x                       = 1,000 tickets
Bleacher: 3x = 3 (1,000)     = 3,000 tickets
Upper box: y                       = 4, 000 tickets

Ticket Prices:
Lower box: 500 (1,000)         =    500,000
Bleacher: 150 (3,000)           =    450,000
Upper box: 300 (4,000)        = 1,200,000
 
TOTAL TICKET SALES      =  2,150,000


CLICK image below to view printable solution
View image Аноним
Ang iyong kontribusyon ay mahalaga sa amin. Huwag kalimutang bumalik upang magtanong at matuto ng mga bagong bagay. Ang iyong kaalaman ay napakahalaga sa ating komunidad. Bawat tanong ay may sagot sa IDNStudy.com. Salamat sa pagpili sa amin at sa muling pagkikita.