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if C(n, 4) =126, what is n ?

Sagot :

C(n,4) = 126

To solve, we need to use combination formula:
          [tex]nCr = \frac{n!}{(n-r)! r!} [/tex]
Substitute the given, the solve;
          [tex] \frac{n!}{(n-4)!4!}=126 [/tex]
          [tex] \frac{n!}{(n-4)! 24} =126 [/tex]
          [tex] \frac{n!}{(n-4)!}=126(24) [/tex]
          [tex] \frac{n!}{(n-4)!} = 3024 [/tex]
          [tex] \frac{n(n-1)(n-2)(n-3)(n-4)!}{(n-4)!} = 9(8)(7)(6) [/tex]
Cancel (n-4)! since it is common to both numerator and denominator.
So,
         [tex]n(n-1)(n-2)(n-3) = 9(8)(7)(6)[/tex]

Since the left side has the same pattern with the right side, then it follows that n = 9. 
 For more learning about combination: https://brainly.ph/question/504738