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Sagot :
Area of rectangle= L × W
Perimeter of rectangle = 2(L) × 2(W)
Width: x
Length: x + 4 (4 cm more than width)
Permimeter: 64 cm
Solve for x using formula of perimeter:
64 = 2 (x) + 2(x + 4)
64 =2x + 2x + 8
64 = 4x + 8
4x = 64 - 8
4x = 56
4x/4 = 56/4
x = 14
Dimension:
Width: x = 14 cm
Length: x + 4 cm = 14 cm + 4 cm = 18 cm
Solve for Area:
Area = L × W
Area = (18 cm) (14 cm)
Area = 252 cm²
ANSWER: The area of rectangle is 252 cm².
Perimeter of rectangle = 2(L) × 2(W)
Width: x
Length: x + 4 (4 cm more than width)
Permimeter: 64 cm
Solve for x using formula of perimeter:
64 = 2 (x) + 2(x + 4)
64 =2x + 2x + 8
64 = 4x + 8
4x = 64 - 8
4x = 56
4x/4 = 56/4
x = 14
Dimension:
Width: x = 14 cm
Length: x + 4 cm = 14 cm + 4 cm = 18 cm
Solve for Area:
Area = L × W
Area = (18 cm) (14 cm)
Area = 252 cm²
ANSWER: The area of rectangle is 252 cm².
Perimeter = 2(l + w)
Area = lw
let x = be the width
x + 4 = be the length
2(x + x + 4) = 64
2(2x + 4) = 64
4x = 64 - 8
[tex] \frac{4x}{4} = \frac{56}{4} [/tex]
x = 14 cm - width
x + 4 = 14 + 4 = 18 cm - length
Area = lw
Area = (14 cm)(18 cm)
Area = 252 cm²
Area = lw
let x = be the width
x + 4 = be the length
2(x + x + 4) = 64
2(2x + 4) = 64
4x = 64 - 8
[tex] \frac{4x}{4} = \frac{56}{4} [/tex]
x = 14 cm - width
x + 4 = 14 + 4 = 18 cm - length
Area = lw
Area = (14 cm)(18 cm)
Area = 252 cm²
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