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Step 1: List the given values.
[tex]\begin{aligned} & mass_{\text{solution}} = \text{4.15 kg = 4150 g} \\ & \%(m/m) = 15.8\% \end{aligned}[/tex]
Step 2: Calculate the mass of solute.
[tex]\begin{aligned} mass_{\text{solute}} & = \frac{\%(m/m)}{100\%} \times mass_{\text{solution}} \\ & = \frac{15.8\%}{100\%} \times \text{4150 g} \\ & = \boxed{\text{655.7 g}} \end{aligned}[/tex]
Hence, there are 655.7 g of nitrogen in 4.15 kg of fertilizer.
[tex]\\[/tex]
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