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The sum of 7 consecutive odd numbers is 113. What is the largest of them?

Sagot :

x = smallest of the 7 consecutive odd number
x + 2 = second
x + 4 = third
...
x + 12 = seventh

x + 2 + x + 4 ... + x + 12 = 133
7x = 133 - 42
7x ÷ 7 = 91 ÷ 7
x = 13 - first
x + 2 = 13 + 2 = 15 - second
...
x + 12 = 13 + 12 = 25 - seventh

Therefore, the answer to your question is 25.

The numbers are 13, 15, 17, 19, 21, 23, 25.