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Hi !! please help me solve this !!
3. A triangular piece of lot has the following dimensions: 30 m, 95 m and 100 m. Determine the biggest angle formed by the three sides of the lot.

Sagot :

Jedidiahpacotidn

Answer:

[tex]225m {}^{2} [/tex]

Step-by-step explanation:

[tex]100 + 95 + 30 = 225m {}^{2} [/tex]

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Answer:

using law of cosine

Step-by-step explanation:

Assuming a= 30m,b=95m,c=100

find the angle of each A,B,C

*For C

c²=a²+b²-2ab cos C

100²=30²+95²-2(30)(95)cosC

10000=9925-5700 cosC

10000/-9925=9925/-9925 -5700cosC

75/-5700= -5700/-5700 cosC

-0.0132=cosC

C=cos^-1(-0.0132)

C=90.76°

For A

a/sin A=c/sinC

30/sinA=100/sin90.76

sinA=30sin90.76/100

sinA=0.299

A=sin^-1(0.299)

A=17.39°

For B

B=180-17.39-90.76

B=71.85°