RandomFangirlidn
Answered

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Sasha invested her $5000 earnings from working abroad in two banks, part at 8% annual interest and the rest at 9%. If the total annual interest for both dollar deposits is %435, how much was invested at each rate?

Sagot :

x + y = 5,000
y = 5,000 - x

Representation:
Investment at Bank 1: x
Investment at Bank 2: 5,000-x

Interest:
Bank 1:  0.08 (x)
Bank 2:  0.09 (5,000-x)

Equation:

0.08 (x) + 0.09 (5,000-x) = 435
0.08x + 450 - 0.9x = 435
0.09x - 0.08x = 450 - 435
0.01x = 15

0.01x/0.01 = 15/0.01
x = 1,500

Investments:
Bank 1: x = $ 1,500
Bank 2: 5,000-1,500 = $3,500

ANSWER: $1,500 invested at 8%  and $ 3,500 invested at 9%.

Check:
Investments:
$1,500 + $3,500 = $ 5,000

Interest:
0.08 ($1,500) + 0.09 ($3,500) = $435
$120 + $315 = $435
$435 = $435


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