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A box contains 4 red socks, 3 blue socks and 3 white socks, when you select at random, replace it and select a second, what is the probability that the first sock is blue and the second is white? *3/10012/1009/1006/100​.

Sagot :

Answer:

9/100

Step-by-step explanation:

4 red socks

3 blue socks

3 white socks

n=10

Solution:

Use independent event since there is the word replace.

3/10 × 3/10 = 9/100

Therefore, the probability that the first sock is blue and the second is white is 9/100.

Answer:

9/100

Step-by-step explanation:

FIrst you find out the probability that the first sock is blue. To do that you do your possibility over your total outcomes.

4 + 3 + 3 = 10

3/10

You have 10 total outcomes and 3 outcomes for the sock to be blue. Now you put 3/10. 3/10 is the probability that the first sock is blue. Now we do this again with finding the probability that the sock is white. We will do the same thing.

4 + 3 + 3 = 10

3/10

3 outcomes for the sock to be white over the 10 total outcomes. 3/10 is also the probability for the white sock as well. Now we must multiply 3/10 by 3/10 to find the probability that the first sock is blue and the second sock is white.

3/10 * 3/10 = 9/100

OR

0.3 * 0.3 = 0.09

Your answer is 9/100 or 0.09.

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