Answered

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Solve the value of a [tex]\large \tt {\sqrt{5a+1}}[/tex]  [tex]\large \tt {+2 = 6}[/tex] ​

Sagot :

ZhylixPhairaidn

Answer:

[tex]\large \tt {a \: = \: 3}[/tex]

Step-by-step explanation:

  • [tex]\large \tt {\sqrt{5a\: + \: 1}}[/tex]  [tex]\large \tt {+2 \: = 6}[/tex]

  • [tex]\large \tt {\sqrt{5a \: + \: 1}}[/tex]  [tex]\large \tt {= 6 \: - 2}[/tex]

  • ([tex]\large \tt {\sqrt{5a \: + \: 1}}[/tex])  [tex]\large \tt {^2 \: = 4^2}[/tex]

  • [tex]\large \tt {5a \: + \: 1 = 16}[/tex]

  • [tex]\large \tt {5a \: = 16 \: - \:1}[/tex]

  • [tex]\large \tt {5a \: = 15}[/tex]

  • [tex]\large \tt \dfrac{5a}{5}[/tex] = [tex]\large \tt \dfrac{15}{5}[/tex]

  • [tex]\large \tt \purple{a \: = \:3}[/tex]

[tex]\: [/tex]

Checking:

Substitute the value of a in the equation

  • [tex]\large \tt {\sqrt{5a\: + \: 1}}[/tex]  [tex]\large \tt {+2 \: = 6}[/tex]

  • [tex]\large \tt {\sqrt{5 \: ⋅ \: 3 \: + \: 1}}[/tex] [tex]\large \tt {+2 \: = 6}[/tex]

  • [tex]\large \tt {\sqrt{15 \: + \: 1}}[/tex] [tex]\large \tt {+2 \: = 6}[/tex]

  • [tex]\large \tt {\sqrt{16}}[/tex] [tex]\large \tt {+ \: 2 \: = 6}[/tex]

  • [tex]\large \tt {4 \: + \: 2 \: = 6}[/tex]

  • [tex]\large \tt \underline{6 \: = 6}[/tex]

Therefore, the solution or the value of the variable is acceptable.