Andrei17621idn
Answered

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Nonsense report

1. Mario claims that he can throw a dart at a dartboard from a distance of 2 meters and hot the 10-cm wide bull's eye if he throws the dart horizontally with a speed of 15 m/s, he starts the throw at the same height as the top of the bull's eye. Will Mario hit the bull's eye?

2. A soccer ball is kicked at ground level with a speed of 15 m/s at an angle of 45° to the horizontal. How much later does it hit the ground?​

Sagot :

Sushimanamiidn

1.

We conclude that Veronica does not hit the bullseye as the full allowance is 5 cm but the height transcended to 0.0872 m

Does Veronica hit the bullseye?

Question Parameters:

a distance of 2 m and hit the 5 cm wide

he dart horizontally with a speed of 15 m/s.

Generally, the equation for the time for the dart to hit is mathematically given as

t = d/v

Therefore

t = 2 /15

t = 0.133 s

Hence

h = 0.5gt^2

h = 0.5(9.81 )(0.133 s)^2

h= 0.0872 m

2.

This question is equivalent to that of a projectile launched at an angle of 30 ° to the horizontal with an initial velocity of 15 m/s .

The distance of the point on the ground where the ball bounces for the 1st time , from the point of projection is basically the range of the projectile motion.

You can use the direct formula for range which is

(u²sin2x)/g =[ {15²sin(2*15)}/10 ] m

= [ ( 225*0.5 )/10 ] m = ( 225/20 ) m = 11.25 m.

Here, u represents initial velocity of projection,

x represents angle of projection with the ground

and

g is the acceleration due to gravit