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A. Atower is 15.24 m high . At acertain distance away from the tower, an observer determines that the angle of
elevation to the top of it is 41*. How far is the observer from the base of the tower?
Solutions:​


Sagot :

Answer

17.53m

Solution

tan41° = Opposite ÷ Adjacent

Adjacent = Opposite ÷  tan41°

= 15.24m ÷ tan41°

= 17.53m