Answer:
GASES: GAY-LUSSAC’S LAW
A carbon dioxide in a tank is at 12 atm and 27 °C. What will be the new pressure if the tank is heated to 100 °C?
GIVEN:
\rm P_1 = 12\: atmP
1
=12atm
\rm T_1 = 27\:\degree CT
1
=27°C
\rm T_2= 100\:\degree CT
2
=100°C
SOLUTION:
Rearrange the equation \rm P_1T_2 = P_2T_1P
1
T
2
=P
2
T
1
to get the equation that will solve for \rm P_2P
2
.
\rm P_2=\frac{P_1T_2}{T_1}P
2
=
T
1
P
1
T
2
Substitute all the given values to solve for the final temperature. The unit °C is cancelled out to give the final unit which is atm.
\rm P_2=\frac{P_1T_2}{T_1}P
2
=
T
1
P
1
T
2
\rm P_2=\frac{(12\:atm)(100\:\degree C)}{27\:\degree C}P
2
=
27°C
(12atm)(100°C)
\rm P_2=\frac{120\: atm}{27}P
2
=
27
120atm
\boxed{\rm P_2=4.44 \: atm}
P
2
=4.44atm
The new pressure if the tank is heated to 100 °C is 2.44 atm.
