SOLUTION:
Step 1: List the given values.
To convert the temperature from degree Celsius to kelvin, add 273.15 to the temperature expressed in degree Celsius.
[tex]\begin{aligned} V_1 & = \text{2,200 mL} \\ T_1 & = -35.0^{\circ}\text{C} = \text{238.15 K} \\ V_2 & = \text{1.34 L = 1,340 mL} \end{aligned}[/tex]
Step 2: Calculate the final temperature (in degree Celsius) by using Charles' law.
To convert the temperature from kelvin to degree Celsius, subtract 273.15 from the temperature expressed in kelvin
[tex]\begin{aligned} T_2 & = \frac{T_1V_2}{V_1} \\ & = \frac{(\text{238.15 K})(\text{1,340 mL})}{\text{2,200 mL}} \\ & = \text{145.06 K} \\ & = \boxed{-128.1^{\circ}\text{C}} \end{aligned}[/tex]
Hence, the temperature of the gas is -128.1°C.
[tex]\\[/tex]
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