Makahanap ng mga solusyon at sagot sa lahat ng iyong katanungan sa IDNStudy.com. Sumali sa aming komunidad ng mga bihasa upang makahanap ng mga sagot na kailangan mo sa anumang paksa o problema.

a sample fluorine gas occupies a volume of 400 ml at 760 torr. given that the temperature remains the same calculate the pressure required to reduce it's volume by
[tex]1 \2[/tex]


Sagot :

GASES: BOYLE’S LAW

A sample fluorine gas occupies a volume of 400 ml at 760 torr. Given that the temperature remains the same calculate the pressure required to reduce its volume by [tex]\frac{1}{2}[/tex].

GIVEN:

  • [tex] \rm P_1 = 760\: torr[/tex]
  • [tex]\rm V_1 = 400 ml[/tex]
  • [tex]\rm V_2= \frac{1}{2}V_1[/tex]

SOLUTION:

Find the value of the final volume.

[tex]\rm V_2= \frac{1}{2}V_1 = \frac{1}{2} (400 \: ml) = 200 \: ml [/tex]

Rearrange the equation [tex]\rm P_1V_1 = P_2V_2[/tex] to get the equation that will solve for [tex]\rm P_2[/tex]

[tex]\rm P_2=\frac{P_1V_1}{V_2}[/tex]

Substitute all the given values to solve for the final temperature. The unit mL is cancelled out to give the final unit which is torr.

[tex]\rm P_2=\frac{P_1V_1}{V_2}[/tex]

[tex]\rm P_2=\frac{(760\:torr)(400\: mL)}{200\: mL}[/tex]

[tex]\rm P_2=\frac{304 \: 000 \: torr}{200}[/tex]

[tex] \boxed{\rm P_2=1 \: 520 \: torr}[/tex]

Convert the pressure in atmosphere, atm, using the equation [tex]\rm atm=\frac{torr}{760}[/tex]

[tex]\rm atm=\frac{torr}{760}[/tex]

[tex]\rm atm=\frac{1 \: 520}{760} = 2 [/tex]

  • Using the same equation, we can say that the initial pressure is at one atmosphere (1 atm).

ANSWER:

Therefore, the pressure required to reduce its volume by [tex]\frac{1}{2}[/tex] is 2 atm.