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find the measure of an interior angle of a regular tridecagon

Sagot :

To find the measure of the interior angle of a polygon, we have the formula...

(n - 2) × 180°

where n is the number of sides. As far as I know, tridecagon have 13 sides.

(13 - 2) × 180°
11 × 180° = 1980

Therefore, the measure of the interior angle of a regular tridecagon is 1980°
Tridecagon = 13-sided polygon

Measure of an/each interior angle of a tridecagon:

= [tex] \frac{180(n-2)}{n} [/tex]     where n = number of sides

= [tex] \frac{180(13-2)}{13} [/tex]

= [tex] \frac{180(11)}{13} [/tex]

= [tex] \frac{1,980}{13} [/tex]

≈ 152.31 degrees.

ANSWER:  An interior angle of a regular tridecagon measures approximately 152.31 degrees.

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To find the sum of the measures of the interior angles of tridecagon:
Sum of interior angles = 180° (13-2)
                                    = 180° (11)
                                    = 1,980°