Cel05idn
Answered

IDNStudy.com, ang iyong pangunahing mapagkukunan para sa mga sagot ng eksperto. Ang aming mga eksperto ay handang magbigay ng malalim na sagot at praktikal na solusyon sa lahat ng iyong mga tanong.

consider a box that contains 14 red balls, 12 blue balls and 9 yellow balls. A ball is drawn at random and the color is notef and then put back inside the box. then, another ball is drawn at random. Find the probability that:
a. Both are blue
b.the first red and the second is yellow

Sagot :

Pingwin09idn
This problem is familiarly known as the "probability of independent events."
a. Let [tex]A=[/tex] the event that the first ball is blue, and [tex]B=[/tex] the event that the second ball is blue.
In the beginning, there are 35 balls in the box, 12 of which are blue. Therefore, expressing it into a probability form as [tex]P(A)= \frac{12}{35} [/tex].
After the first selection, the ball was returned to the box making the number of balls in the box still equal to 12 blue, 14 red, and 9 yellow balls. So [tex]P(B|A)= \frac{12}{35} [/tex].
Thus, multiplying the two probabilities yields
[tex]P_A_a_n_d_B= \frac{12}{35}( \frac{12}{35} )= \frac{144}{1225}=0.11755 [/tex]

b. Let [tex]A=[/tex] the event that the first ball is red, and [tex]B=[/tex] the event that the second ball is yellow.
Again there are 35 balls, 14 of which are red: [tex]P(A)= \frac{14}{35} [/tex]
For the second selection to be a yellow ball (as which the returning of the first ball to the box is allowed), [tex]P(B|A)= \frac{9}{35} [/tex]
Thus, [tex]P_A_a_n_d_B= \frac{14}{35}( \frac{9}{35} )= \frac{18}{175}=0.10286 [/tex]


Salamat sa iyong pakikilahok. Patuloy na magbahagi ng iyong mga ideya at kasagutan. Ang iyong ambag ay napakahalaga sa aming komunidad. Bawat tanong ay may sagot sa IDNStudy.com. Salamat at sa muling pagkikita para sa mas maraming solusyon.