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pedro spent 1/2 in the first store then he spent 1/4 of what he had left in the second store.after he spent 60 pesos in the third store ,he had no money left.how much did he have at first?

Sagot :

BrokenScene01idn
P240 is the answer
because 60 is your basis and 1/2 and 1/4 are your guide so you need to form 1 whole. 60 is just 1/4. multiply 60 x 4. that's the answer.
Pedro's money: x
Money spent on first store: ¹/₂ (x)
Money spent on second store: ¹/₄ (¹/₂) (x) 
Money spent on third store: 60

Equation:

x - [ 1/2(x) + 1/4 (1/2)(x) + 60) ] = 0
x - [ 1/2(x) + 1/8(x) + 60 ] = 0

Change the sign of each term of the subtrahend [1/2(x) + 1/8 (x) + 60]:
x + [-¹/₂ x - ¹/₈ x - 60] = 0
x + (-⁴/₈ x - ¹/₈ x) - 60 = 0
x - ⁵/₈ x = 60

LCD: 8
(8)x - (8) ⁵/₈ x = (8) (60)
8x - 5x = 480
3x = 480
3x/3 = 480/3
x = 160

ANSWER: Pedro has Php160 at first.

To check, subtract the expenses from Php160:

First store: ¹/₂ x = ¹/₂ (160) = 80 pesos
Second store: (¹/₄) (¹/₂) (160) = ¹/₈ (160) = 20 pesos
Third Store: 60 pesos
Expenses:  80 + 20 + 60 = 160

160 - 160 = 0 ( No money left or all money were spent on three stores)



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