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Find an interval of values for Z using the standard normal distribution corresponding to an area of 85%​

Sagot :

Answer:

Firstly we need to find #alpha# the area of which we don't want, which would be #alpha = 1 - 80% = 1 - 0.8 = 0.2#.

we also know that our Standard Normal Distribution is symmetric, so we would like to divide the area we don't want to be on either side of our area, so we solve for:

#alpha/2 = 0.2/2 = 0.1#

now it becomes easy to solve for #-z# using our table.

Which gets us:

#-z = -1.285# and then #z = 1.285#

This is easier do do if you draw it out: