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PROBLEM:
In a batch of 860 calculators, 9 were found to be defective. What is the probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.
ANSWER:
The probability that a calculator chosen at a radom will be defective can be written as 9/860. Note that probability refers to the favorable outcomes divided by the possible outcomes (sample space).
\begin{gathered} \tt{P=\frac{favorable \: outcomes}{possible \: outcomes} = \frac{9}{860} }\\\end{gathered}
P=
possibleoutcomes
favorableoutcomes
=
860
9
In this problem's case, the favorable outcome is the number of defective calculators, 9, while the possible outcome is the total number of calculators, 860.
But! We need to write the probability as percent. Before that, let us first divide 9 by 860 to have a decimal number as an answer, then multiply it by 100 to get the percent.
\begin{gathered} \tt \frac{9}{860} = 0.010 \times 100 = 1.0 \%\\\end{gathered}
860
9
=0.010×100=1.0%
Therefore, the probability is 1.0%.