Glenjadulcoidn
Answered

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MATH CHALLENGE (TRANSFER OF KNOWLEDGE)

• Prove that in a right triangle, the other two angles are both acute. Use the direct method. (25pts​

Sagot :

Brieyllebon7idn

Answer:

I’m not sure what the direct method is, but here’s my proof.

RULES : The sum of angles in a triangle is 180 degrees. There is no such thing as a negative, or zero, angle in a polygon.

Let a,b and c be the three angles in a right triangle. let a be the right (90 degree) angle.

a+b+c = 180

a = 90, so b+c = 90.

0 < b, because b cannot be less than (or equal to) zero, by the rules

b < 90 because if b >= 90, then c <= 0, which breaks the rules.

Therefore, 0<b<90, making b an acute angle. A similar proof follows for c.

Nikaferreras593idn

Answer:

I’m not sure what the direct method is, but here’s my proof.

RULES : The sum of angles in a triangle is 180 degrees. There is no such thing as a negative, or zero, angle in a polygon.

Let a,b and c be the three angles in a right triangle. let a be the right (90 degree) angle.

a+b+c = 180

a = 90, so b+c = 90.

0 < b, because b cannot be less than (or equal to) zero, by the rules

b < 90 because if b >= 90, then c <= 0, which breaks the rules.

Therefore, 0<b<90, making b an acute angle. A similar proof follows for c.

Step-by-step explanation:

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