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1. Calculate the molar concentration of a solution that contains 18g KOH in 220mL solution.​

Sagot :

SOLUTION:

Step 1: Calculate the number of moles of solute (KOH).

Note that the molar mass of KOH is 56.11 g/mol.

[tex]\begin{aligned} \text{moles of solute} & = \frac{\text{mass of solute}}{\text{molar mass of solute}} \\ & = \frac{\text{18 g}}{\text{56.11 g/mol}} \\ & = \text{0.3208 mol} \end{aligned}[/tex]

Step 2: Solve for the molarity of solution.

Note that 1 molar (M) = 1 mole per liter (mol/L).

[tex]\begin{aligned} \text{molarity} & = \frac{\text{moles of solute}}{\text{volume of solution}} \\ & = \frac{\text{0.3208 mol}}{\text{0.220 L}} \\ & = \text{1.46 mol/L} \\ & = \boxed{1.46 \: M} \end{aligned}[/tex]

Hence, the molar concentration of the solution is 1.46 M.

[tex]\\[/tex]

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