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Ohm's Law
Power Revisited
There are certain formulas that are so powerful and so pervasive that they reach the state of popular knowledge. A student of Electrical technology has written such formulas down so many times that they have memorized it without trying to. Certainly to the professionals in the field, such formulas are so central that they become engraved in their minds. In the field of Modern Physics, there is [tex]\small\tt\red{E = m • c2}[/tex]. In the field of Newtonian Mechanics, there is [tex]\small\tt\color{red}{Fnet = m • a}[/tex]. In the field of Wave Mechanics, there is [tex]\small\tt\color{red}{v = f • λ}[/tex]. And in the field of current electricity, there is[tex]\small\tt\color{red}{V = I • R}[/tex].
The predominant equation which pervades the study of electric circuits is the equation.[tex]\small\tt\red{V = I • R}[/tex]
In words, the electric potential difference between two points on a circuit (V) is equivalent to the product of the current between those two points (I) and the total resistance of all electrical devices present between those two points (R). Through the rest of this unit , this equation will become the most common equation which we see. Often referred to as the Ohm's law equation, this equation is a powerful predictor of the relationship between potential difference, current and resistance.
Ohm's Law as a Predictor of Current
The Ohm's law equation can be rearranged and expressed as:
As an equation, this serves as an algebraic recipe for calculating the current if the electric potential difference and the resistance are known. Yet while this equation serves as a powerful recipe for problem solving, it is much more than that. This equation indicates the two variables that would affect the amount of current in a circuit. The current in a circuit is directly proportional to the electric potential difference impressed across its ends and inversely proportional to the total resistance offered by the external circuit. The greater the battery voltage (i.e., electric potential difference), the greater the current. And the greater the resistance, the less the current.
And an increase in the resistance of the load by a factor of two would cause the current to decrease by a factor of two to one-half its original value.
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[tex] \large \mathbb \color{red}{ANSWER:}[/tex]
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