Answer:
Step-by-step explanation:
1. A box is (2×-3) by (×+5) by (3×+1), what is the volume of the box
if x = 3cm ?
Volume of the box is equal to x x , or simply multiply all its dimensions - length, width, and height. If x = 3, then
(2×-3) (×+5)(3×+1) = [(2)(3)-3](3+5)[(3(3)+1)] = ( 3)(8)(10) = 240
Therefore, Volume=240
2. The formula for the area of a triangle is A=bh/2. If the base (b)=10cm and height(h)=6cm, what is the area of the triangle?
Since area, A = BH/2 = (10 x 6) / 2 = 30
Therefore, Area = 30
3. The length(l) of the rectangle is x²+2×-3 and width(w) is 5×+4 What is the perimeter of the rectangle?
Perimeter of a rectangle is equal to the sum of twice of its length and twice of its width, P = 2L + 2W.
2 x (x²+2×-3) + 2 x (5×+4) = 2x²+4×-6+10×+8 = 2x²+14x+2
Therefore, Perimeter of the rectangle = 2x²+14x+2 units
4. From the sum of 3׳+7ײ-5 and 2ײ + 3×+8 take away 5ײ+×-5.
(3׳+7ײ-5) + (2ײ + 3×+8) - (5ײ+×-5) = (3׳+9ײ+3x+3)-(5ײ+×-5)
= 3׳+4ײ+4x-2
5. What should be added to 3׳+4ײ-7 to have a sum of 4׳+ײ+5?
(4׳+ײ+5) - (3׳+4ײ-7) = (׳-3ײ+12)
Therefore, (׳-3ײ+12) should be added to (3׳+4ײ-7) to have a sum of (4׳+ײ+5.
