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how many atoms are present in 35.8 grams of sodium

Sagot :

Indrawboyidn

Number of atoms are present in 35.8 grams of sodium : 9.373.10²³

Further explanation

Atoms are composed of 3 types of basic particles namely protons, electrons, and neutrons

the mass of this basic particle is expressed in  atomic mass  units (amu)

This atomic unit uses the standard atomic mass, that is, the C-12 isotope

1 atom C-12 = 12 atomic mass units

1 atomic mass unit = 1/12 x mass 1 C-12 atom

Mole itself is the number of particles contained in a substance

1 mole = 6.02.10²³ particles

Mole can be determined if the amount of substance mass and its molar mass is known

[tex]\large {\boxed {\boxed {\bold {mole = \dfrac {mass} {molar \: mass}}}}[/tex]

Sodium(Na) is an element in group 1A and in period 3 with atomic number 11 with atomic mass (Ar) = 23

35.8 grams of sodium

then the mole of Sodium:

[tex]\rm mole=\dfrac{35.8}{23}\\\\mole=\boxed{1,557}}[/tex]

so the number of atoms:

[tex]=1,557\times 6.02.10^{23}\\\\=9.373.10^{23}[/tex]

Learn more  

the mole fractions of the solute and the solvent  

https://brainly.ph/question/2062141  

moles of CaCO3  

https://brainly.ph/question/2356002  

the mole ratio of Al to Cl2  

https://brainly.ph/question/2124499

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