Makakuha ng detalyadong mga sagot sa iyong mga tanong gamit ang IDNStudy.com. Sumali sa aming platform ng tanong at sagot upang makakuha ng eksaktong tugon sa lahat ng iyong mahahalagang tanong.
Sagot :
[tex] x_{1} =4[/tex]
[tex] x_{2} [/tex] = -6
[tex] y_{1} [/tex] = -3
[tex] y_{2} [/tex] = -5
d = [tex] \sqrt{(x_{2}- x_{1})^{2} + (y_{2} - y_{1})^{2} } [/tex]
d = [tex] \sqrt{(4-(-6))^{2} + (-3- (-5)) ^{2} } [/tex]
d = [tex] \sqrt{(-10)^{2}+ (-2) ^{2} } [/tex]
d = [tex] \sqrt{100+4} [/tex]
d = [tex] \sqrt{104} [/tex]
d = [tex] \sqrt{4 · 26} [/tex]
d = 2[tex] \sqrt{26} [/tex]
[tex] x_{2} [/tex] = -6
[tex] y_{1} [/tex] = -3
[tex] y_{2} [/tex] = -5
d = [tex] \sqrt{(x_{2}- x_{1})^{2} + (y_{2} - y_{1})^{2} } [/tex]
d = [tex] \sqrt{(4-(-6))^{2} + (-3- (-5)) ^{2} } [/tex]
d = [tex] \sqrt{(-10)^{2}+ (-2) ^{2} } [/tex]
d = [tex] \sqrt{100+4} [/tex]
d = [tex] \sqrt{104} [/tex]
d = [tex] \sqrt{4 · 26} [/tex]
d = 2[tex] \sqrt{26} [/tex]
I don't see the use of using the distance formula so I'm going to use the midpoint formula
The midpoint formula is:
[tex]( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )[/tex]
So we plug in the values with (4,-3) being x₁ and y₁ and (-6,-5) being x₂ and y₂.
[tex]( \frac{4-6}{2},\frac{-3-5}{2} ) \\\\ ( \frac{-2}{2},\frac{-8}{2} )\\\\(-1,-4)[/tex]
The coordinates of the center of the diameter of the circle with the given points is (-1,-4)
The midpoint formula is:
[tex]( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )[/tex]
So we plug in the values with (4,-3) being x₁ and y₁ and (-6,-5) being x₂ and y₂.
[tex]( \frac{4-6}{2},\frac{-3-5}{2} ) \\\\ ( \frac{-2}{2},\frac{-8}{2} )\\\\(-1,-4)[/tex]
The coordinates of the center of the diameter of the circle with the given points is (-1,-4)
Pinahahalagahan namin ang bawat tanong at sagot na iyong ibinabahagi. Huwag kalimutang bumalik at magtanong ng mga bagong bagay. Sama-sama tayong magtatagumpay. Umaasa kami na natagpuan mo ang hinahanap mo sa IDNStudy.com. Bumalik ka para sa mas maraming solusyon!