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The gravitational force between two bodies varies inversely as the square of the distance between them. If the force between two bodies is 18 N when the distance between them is 10 km, find the fource between the bodies when the distance between them is 7.5 km.




Sagot :

F = k/d²  where k is constant of the inverse variation

18 N = k / (10 km)²
18 N = k / 100 km²
k = (18 N) (100 km²)
k = 1 800 (N)(km²)

F = ?
d = 7.5 km
k = 1 800 (N) (km²)

F = 1 800 (N)(km²) / (7.5 km)²
F = 1 800 (N) (km²) / (55.25 km²)
F = 32 N