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if a line has x and y intercepts 3 and -1/2 respectively?

Sagot :

To get the equation of the line when yu are given the x and y intercepts, you can use the two intercept form which is:

x/a + y/b = 1, where a and b are the x and y intercepts respectively.

Substituting 3 and -1/2 into the equation, we get

x/3 + y/(-1/2) = 1
x/3 - 2y = 1
x - 6y = 3

x - 6y - 3 = 0