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Please help〒▽〒 Triangle Similarity

Please Help Triangle Similarity class=

Sagot :

Answer:

1. △ABC and △PQR are isosceles triangle since its two sides are congruent. Hence in △ABC, ∠B can be determined as ∠B = 180 - 2(70) = 40°. From this we can conclude that ∠B ≅ ∠Q. Also, since the two triangles are isosceles triangles, the ratio of their corresponding sides are equal. Therefore, △ABC∼△PQR using SAS Similarity.

2. Given that BE and CD are parallel, ∠AEB ≅ ∠ADC and ∠ABE ≅ ∠ACD since they are corresponding angles. Hence, we can conclude that △ABE∼△ACD by AAA Similarity.

[tex]\frac{x}{3} =\frac{x+6}{3+4.5}[/tex]

[tex]7.5x=3x+18[/tex]

[tex]x=\frac{18}{7.5-3} =4[/tex]

[tex]BE=x=4[/tex]

[tex]CD=x+6=4+6=10[/tex]